1 Kayla's family is looking on a website for a vacation house to rent. They can
choose a two- or three-bedroom house. The houses are either one story or two
stories tall, and some houses allow pets, while others do not. What are all the
possible outcomes?
All of the possible outcomes are equally likely. What is the probability that a house
chosen at random will have three bedrooms and two stories?

Respuesta :

To determine the number of possible outcomes for the vacation houses, we can break down the choices Kayla's family can make:

1. Number of bedrooms: 2 options (two-bedroom or three-bedroom).
2. Number of stories: 2 options (one story or two stories).
3. Pet policy: 2 options (allows pets or does not allow pets).

To find all possible outcomes, we multiply the number of options for each category: 2 (bedrooms) 2 (stories) 2 (pet policy) = 8 possible outcomes.

Therefore, there are 8 possible outcomes when choosing a vacation house.

To calculate the probability of selecting a house with three bedrooms and two stories, we need to identify how many outcomes meet these criteria.

There is only 1 outcome that fits the criteria of having three bedrooms and two stories. So, the probability of choosing a house with three bedrooms and two stories out of the 8 possible outcomes is:

1 favorable outcome / 8 total outcomes = 1/8 = 0.125 or 12.5%.

Therefore, the probability that a randomly chosen house will have three bedrooms and two stories is 12.5%.