Respuesta :
3n = 11+2 (n+2) n= lesser number
3n = 11+2n+4. (n+2)= greater number
3n = 15+2n
3n-2n=15
n=15
15×3 =11+((15+2)×2)
the numbers are 15 and 17
3n = 11+2n+4. (n+2)= greater number
3n = 15+2n
3n-2n=15
n=15
15×3 =11+((15+2)×2)
the numbers are 15 and 17
Answer:
Smaller is 15 and greater is 17
Step-by-step explanation:
Let the lesser of the two consecutive odd numbers be x
then greater will be x+2 .
three times of lesser = 3x
two times of greater = 2(x +2)
11 more than 2x = 11+2(x+2)
according to the question .
3x = 11 +2(x+2)
3x= 11 +2x+4
3x-2x = 15
x = 15
Smaller is 15 and greater is 17
