Find the equation of the line that passes through the point left-parenthesis 1 comma 2 right-parenthesis and is perpendicular to the line negative startfraction 5 over 6 endfraction x plus startfraction 6 over 5 endfraction y equals negative 5

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09-09-2017
Mathematics

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Find the equation of the line that passes through the point left-parenthesis 1 comma 2 right-parenthesis and is perpendicular to the line negative startfraction 5 over 6 endfraction x plus startfraction 6 over 5 endfraction y equals negative 5

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texaschic101 texaschic101 · Answer 1 · 2017-09-09T14:03:12+02:00

5/6x + 6/5y = -5
6/5y = -5/6x - 5...multiply by 30
36y = -25x - 150
y = -25/36x - 25/6....the slope here is -25/36. A perpendicular line will have a negative reciprocal slope. All that means is flip the original slope and change the sign. So the perpendicular line will have a slope of 36/25.

y = mx + b
slope(m) = 36/25
(1,2)...x = 1 and y = 2
now we sub and find b, the y int
2 = 36/25(1) + b
2 = 36/25 + b
2 - 36/25 = b
50/25 - 36/25 = b
14/25 = b

so ur perpendicular equation is : y = 36/25x + 14/25

summerall02 summerall02 · Answer 2 · 2019-10-09T20:44:57+02:00

Answer:

5/6x + 6/5y = -5

6/5y = -5/6x - 5...multiply by 30

36y = -25x - 150

y = -25/36x - 25/6....the slope here is -25/36. A perpendicular line will have a negative reciprocal slope. All that means is flip the original slope and change the sign. So the perpendicular line will have a slope of 36/25.

y = mx + b

slope(m) = 36/25

(1,2)...x = 1 and y = 2

now we sub and find b, the y int

2 = 36/25(1) + b

2 = 36/25 + b

2 - 36/25 = b

50/25 - 36/25 = b

14/25 = b

so ur perpendicular equation is : y = 36/25x + 14/25

Step-by-step explanation: