Respuesta :

x^4 - 3x^2 + 2
= (x^2 - 1)(x^2 - 2)
Note that x^-1 is the difference of 2 squares:-
= (x + 1)(x - 1)(x^2 - 2)   Answer
mreijepatmat
I guess you want to find its roots (its zeros). If so then:

Le X = x²

X²-3X+2 = 0 Solve this quadratic equation:

X₁ = [-b+√(b² - 4.a.c)]/2a   and X₂ = [-b-√(b² - 4.a.c)]/2a  

X₁ = [+3+√(9-8)]/2   X₂ = [+3-√(9-8)]/2

X₁ = 4/2 = 2    and X₂ = 2/2 = 1

but X = x² , then:

x' = +√X₁  and x" = - √X₁; x"' = +√X₂  and x"" = -√X₂

x' = √2, x" = -√2; x'" = 1 and x"" = -1

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