Respuesta :

mreijepatmat
In a quadratic function, y = a(x²) the smaller the coefficient "a", the larger is the parabola:
From widest to narrowest:

1) y=1/3x² (Widest)

2) y= -1/2x² (Wider)

3) y=-9x² (narrowest)

Answer:

The parabola represented by equation [tex]y=\frac{1}{3}x^2[/tex] is widest

The parabola represented by equation [tex]y=-\frac{1}{2}x^2[/tex] is wider

and the parabola represented by equation [tex]y=-9x^2[/tex] is narrowest

Step-by-step explanation:

we know that equation of parabola is given as,

[tex]y= ax^2[/tex]

Here,

a is a constant which decide the size of parabola

if value of a is larger than the parabola will be wider

here

we have given three parabola

[tex]y=-9x^2, y=\frac{1}{3}x^2, y=\frac{-1}{2}x^2[/tex]

and it is clear that

[tex]-9<-\frac{1}{2}<\frac{1}{3}[/tex]

Therefore

The parabola represented by equation [tex]y=\frac{1}{3}x^2[/tex] is widest

The parabola represented by equation [tex]y=-\frac{1}{2}x^2[/tex] is wider

and the parabola represented by equation [tex]y=-9x^2[/tex] is narrowest

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