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A cyclist leaves home and rides due east for a distance of 45 km. She returns home on the same bike path. If the entire trip takes 4 hrs, what is her average speed? What is her displacement ?

Respuesta :

90km/4hrs=22.5kn/hr average speed. Her dispacement is 0. Her trip started and ended in the same place.

Answer:

The average speed is 22.5 km/hr and displacement is zero.

Explanation:

Given that,

Distance of one side = 45 km

Time = 4 hrs

We need to calculate the average speed

Using formula of average speed

[tex]v = \dfrac{D}{T}[/tex]

Where, D = total distance

T = total time

Put the value into the formula

[tex]v = \dfrac{90}{4}[/tex]

[tex]v=22.5\ km/hr[/tex]

Displacement will be zero because the journey ends where the journey stated.

Hence, The average speed is 22.5 km/hr and displacement is zero

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