Answer:
38 m/min (Diving)
Step-by-step explanation:
First, let's establish a reference system on which the surface of the sea is the 0 value, with positive values above it, and negative values below it.
So we see that the position of the submarine at initial time (t₀ = 0 min) is -29m, and that the position after 6 minutes (t₆ = 6 min) is -257m.
Now, we know that Velocity is given by:
V = Δy/Δt;
This is:
V = (y₆ - y₀)/(t₆-t₀)
Replacing, we get
V = (-257-(-29))/(6-0);
V = (-257+29)/6;
V = -38m/min (The negative sign indicates that the submarine is diving)
We know that the speed is the absolute value of the speed, so
|V| = 38m/min
