First we have to find [tex]\Delta [/tex] from the equation [tex] b^{2} -4ac[/tex] where a, b and c are consecutive coefficients of the equation. In this case: [tex]a=1, b=4, c=-6[/tex]
[tex]\Delta =4^2-4*(-6)=16+24=40 [/tex],
Later we will need to use [tex]\sqrt{\Delta} [/tex] sofor us [tex]\sqrt{40} [/tex]. It can be then simplified to [tex]2 \sqrt{10} [/tex].
Then we use quadratic formula [tex]x=\frac{-b\pm \sqrt{\Delta} }{2a} [/tex] to see what are the options for x.
[tex]x=\frac{-4\pm 2\sqrt{10}}{2}[/tex]
[tex]x=- 2 \pm \sqrt{10} [/tex]
The answer for your question:
[tex]x=- 2 + \sqrt{10}[/tex] or [tex]x=- 2 - \sqrt{10}[/tex]
