Respuesta :
The answer is Na-F. The F has highest electronegativity among these elements. So we need to find the element with smallest electronegativity. And this element is Na.
Answer: Na-F has the highest electronegativity difference.
Explanation: Electronegativity is the measure of how strongle an atom holds the electrons. The highest electronegative atom is Fluorine.
- Electronegativity of Sodium = 0.93
- Electronegativity of Calcium = 1
- Electronegativity of Hydrogen = 2.1
- Electronegativity of Carbon = 2.55
- Electronegativity of Fluorine = 3.98
Electronegativity difference in the following compounds:
- Electronegativity difference in Na-F = 3.98 - 0.93 = 3.05
- Electronegativity difference in Ca-F = 3.98 - 1 = 2.98
- Electronegativity difference in H-F = 3.98 - 2.1 = 1.88
- Electronegativity difference in C-F = 3.98 - 2.55 = 1.43
- Electronegativity difference in F-F = 3.98 - 3.98 = 0
From the above calculations, it is visible that the highest electronegativity difference is present in Na-F.
From all the compounds, it is clearly seen that sodium can loose the electrons easily and is most electropositive and fluorine is the most electronegative element.