Respuesta :
[tex]x-2y=24 \ \ \ \ \ \ \ \ \ \ \ \ \ | \times (-3) \\
3x-6y=72 \\ \\
-3x+6y=-72 \\
\underline{3x-6y=72 \ \ \ \ \ \ \ } \\
3x-3x+6y-6y=72-72 \\
0=0 \\
always \ true \\ \\
\hbox{infinitely many solutions}[/tex]
The answer is B.
The answer is B.
solve your system of equations.
−2y=24;3x−6y=72
Solve −2y=24 for y:
−2y/−2 = 24/−2(Divide both sides by -2)
y=−12
Substitute (−12) for y in 3x−6y=72:
3x−6y=72
3x+(−6)(−12)=72
3x+72=72(Simplify both sides of the equation)
3x+72+−72=72+−72(Add -72 to both sides)
3x=0
3x/3 = 0/3(Divide both sides by 3)
x=0
Answer B)
−2y=24;3x−6y=72
Solve −2y=24 for y:
−2y/−2 = 24/−2(Divide both sides by -2)
y=−12
Substitute (−12) for y in 3x−6y=72:
3x−6y=72
3x+(−6)(−12)=72
3x+72=72(Simplify both sides of the equation)
3x+72+−72=72+−72(Add -72 to both sides)
3x=0
3x/3 = 0/3(Divide both sides by 3)
x=0
Answer B)