There are 4+6=10 chips in the bag. 4 of them are white. The probability that the first chip chosen will be white is 4/10=2/5.
After that, there is one white chip less in the bag, so there are 9 chips in the bag, 3 of them are white. The probability that the second chip chosen will be white is 3/9=1/3.
Multiply the probabilities to find the probability that the first chip will be white and the second chip will be white:
[tex]\frac{2}{5} \times \frac{1}{3}=\frac{2}{15}[/tex]
The probability of choosing a white chip and then another white chip is 2/15.
