[tex]A(3;\ 4);\ B(2;-1)\\\\the\ slope: m=\frac{y_B-y_A}{x_B-x_A}\\\\therefore\\\\m=\frac{-1-4}{2-3}=\frac{-5}{-1}=\fbox{5}\\\\the\ slope-intercept\ form:y=mx+b\\\\find\ "b":\\subtitute\ the\ values\ of\ coordinates\ of\ the\ point\ B\ to\ the\ equation:\\y=5x+b\\\\B(2;-1)\to x=2\ and\ y=-1\\\\-1=5(2)+b\\-1=10+b\ \ \ \ |subtract\ 10\ from\ both\ sides\\-11=b\\\\Your\ answer:\boxed{y=5x-11}[/tex]
