Respuesta :
solve for a.
(8z−9)(8z+9)=az2−b
Flip the equation.
az2−b=64z2−81
Add b to both sides.
az2−b+b=64z2−81+b
az2=64z2+b−81
Divide both sides by z^2.
[tex]\bold{ \frac{az^2}{z^2} = \frac{64z^2 + b - 81}{z^2}} \\ \\ a = \pmb{ \boxed{\boxed{\boxed{\frac{64z^2 + b - 81}{z^2} }}}}[/tex]
(8z−9)(8z+9)=az2−b
Flip the equation.
az2−b=64z2−81
Add b to both sides.
az2−b+b=64z2−81+b
az2=64z2+b−81
Divide both sides by z^2.
[tex]\bold{ \frac{az^2}{z^2} = \frac{64z^2 + b - 81}{z^2}} \\ \\ a = \pmb{ \boxed{\boxed{\boxed{\frac{64z^2 + b - 81}{z^2} }}}}[/tex]
The people that are answering this arn't doing it affectivly because there not realizing, B=2. Add that to there equation and simplify it.