Respuesta :
Answer:8 grams of glucose are needed to prepare 400. ml of a 2.0%(m/v) glucose solution.
Explanation:
Volume of the solution = 400 mL
Mass by volume percentage of the solution = 2%
Mass of the glucose = m
The mass by volume percent is given by formula ;
[tex](m/v\%)=\frac{\text{mass of the solute}}{\text{Volume of the solution}}\times 100[/tex]
[tex]2\%=\frac{m}{400}\times 100[/tex]
m = 8 g
8 grams of glucose are needed to prepare 400. ml of a 2.0%(m/v) glucose solution.
Mass Concentration is generally denoted as mass of solute (in grams) per ml volume of solution.
Mass Concentration:
It is generally denoted as mass of solute (in grams) per ml volume of solution. It can be calculated by formula,
[tex]\bold {p = \frac{m}{v} \times 100 }[/tex]
Where,
p = mass concentration (m/v%) = 2%
m = mass in grams = ?
v = volume in mL = 400mL
Put the values in the formula
[tex]\bold {2 = \frac{m}{400} \times 100 }[/tex]
[tex]\bold { m = 8 }[/tex]
Hence, we can conclude that the 8 g of glucose is needed to prepare 400mL of a 2%(m/v) solution.
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