Answer:
c Kayla is answer
Step-by-step explanation:
Since sine lies between-1 and +1 we have cosecant, reciprocal of sin lying always outside -1 and 1.
i.e. |cosec x|>1
For acute angle sine, cos , tan are positive
So cosec x >1 and similarly since cos x <1, sec x >1 always
But tanx varies between 0 and infinity for acute angles
Hence cot can take values from 0 to infinity
Hence the correct answer is that of Kayla
The cosecant and secant of an acute angle are always greater than 1, but the cotangent can be greater than 1, less than 1 or equal to 1.
The statement about cosecant, secant, and cotangent values that is correct is Kayla's: The cosecant and secant of an acute angle are always greater than 1, but the cotangent can be greater than 1, less than 1 or equal to 1.
In Trigonometry, the sine of an acute angle is a ratio of the length of an opposite side of a right-angled triangle to the length of its hypotenuse. Also, the sine of an angle generally lies between -1 and 1.
In Trigonometry, the cosecant (cosec) of an acute angle is a ratio of the length of its hypotenuse to the length of an opposite side of a right-angled triangle. Thus, the cosecant of an angle is the reciprocal of the sine function and as such lies outside -1 and 1.
The cotangent of an acute angle is a ratio of the length of its adjacent side to the length of an opposite side of a right-angled triangle.
In conclusion, Kayla's statement about the values of cosecant, secant, and cotangent is correct.
Read more on cosecant here: https://brainly.com/question/23419192
