contestada

Which functions have graphs that are steeper than the graph of f(x)=−3x^2?

Select each correct answer.

h(x)=−2x^2

g(x)=−4x^2

k(x)=3x^2

m(x)=4x^2

j(x)=2x^2

Need help asap please

I think it is k(x)=3x^2 and j(x)=2x^2 Can anyone tell me if i am correct.

Respuesta :

Answer:

g(x)=−4x^2  and m(x)=4x^2

Step-by-step explanation:

A horizontal stretch or shrink happens when you multiply the parent function (in this case f(x) = x²) by a number.  If this number is between 0 and 1, the graph will be stretched horizontally.  If this number is greater than 1, the graph will be shrunk horizontally.  If the number is between -1 and 0, the graph will be stretched horizontally and flipped; if the number is less than -1, the graph will be shrunk horizontally and flipped.

The graphs that are horizontally shrunk are steeper than the others.  This is m(x)=4x^2  and g(x) = -4x^2.

   If the parent function f(x) = x is stretched vertically by a scale factor 'k', image function will be,

   g(x) = kf(x)

It's inverted form will be,

  h(x) = -kx

Functions given in options (2) and (4) will be more steeper than function 'f'.

  Given function is f(x) = -3x²

Functions having scale factor 'k' more than 3 will be more stretched vertically.

Hence, functions having k > 3 will be more steeper.

From the given options, g(x) = -4x², m(x) = 4x² have coefficient 'k' greater than 3.

Therefore, functions 'g' and 'm' will be more steeper than function 'f'.

      Options (2) and (4) are the correct options.

Learn more,

https://brainly.com/question/13815011

Otras preguntas