the zeroes
the serose of the x value is where y=0,
that is where profit=0
the zeroes of the y value is where x=0
that's when the price is 0 dollars
ok
x zeroes
solve for when y=0
[tex]0=-3(x-2)^2+6[/tex]
[tex]-6=-3(x-2)^2[/tex]
[tex]2=(x-2)^2[/tex]
[tex]+/-\sqrt{2}=x-2[/tex]
[tex]2+/-\sqrt{2}=x[/tex]
x zeroes at [tex]x=2+\sqrt{2}[/tex] and [tex]x=2-\sqrt{2}[/tex]
y zeroes
x=0
[tex]y=-3(0-2)^2+6[/tex]
[tex]y=-3(-2)^2+6[/tex]
[tex]y=-3(4)+6[/tex]
[tex]y=-12+6[/tex]
[tex]y=-6[/tex]
the y zeroes are where they sell 0 hot dogs for 0 dollars, it is $-6 profit
the x zereoes are where you make 0 profit, that occurs when you sell [tex]2+\sqrt{2}[/tex] and [tex]2-\sqrt{2}[/tex] hot dogs
not sure which answer you want because it doesn't specify which zeroes we want
A is wrong tho
