Respuesta :
The question states that z divided by 8, or z/8 has a remainder of 5. That means that 8 goes into z 5 times, but has a remainder of 5, meaning that 8*5+5=z=45. To find 4z, we multiply 45 by 4 to get 180. Next, we use long division to divide that by 8.
22
______
8 | 180
-160
____
20
-16
___
4. This can be done due to that 8 does not go into 1, but 8*2=16, and 8*3=24. Keep in mind that since 8 doesn't go into 1, the 1 moves over with the 8 to form 18. Next, we have 18-16=2, and we add a 0 at the end because 180 has 3 digits. We repeat the process for 20, and at the end, since 8 does not go into 4, we have a remainder of 4
22
______
8 | 180
-160
____
20
-16
___
4. This can be done due to that 8 does not go into 1, but 8*2=16, and 8*3=24. Keep in mind that since 8 doesn't go into 1, the 1 moves over with the 8 to form 18. Next, we have 18-16=2, and we add a 0 at the end because 180 has 3 digits. We repeat the process for 20, and at the end, since 8 does not go into 4, we have a remainder of 4
The remainder when 4z is divided by 8 is 4
From the question, when z is divide by 8, the remainder is 5. But we do not know the quotient.
From the formula
[tex]\frac{Dividend}{Divisor}= Quotient + \frac{Remainder}{Divisor}[/tex]
Here, the dividend is z, divisor is 8, and the remainder is 5.
Let the quotient be x, then we can write that
[tex]\frac{z}{8} = x + \frac{5}{8}[/tex]
Now, to determine the remainder when 4z is divided by 8,
Multiply both sides of the equation by 4
[tex]4 \times\frac{z}{8} =4\times( x + \frac{5}{8})[/tex]
[tex]\frac{4z}{8} = 4x + \frac{20}{8}[/tex]
Then,
[tex]\frac{4z}{8} = 4x +2+ \frac{4}{8}[/tex] (NOTE: [tex]\frac{Remainder}{Divisor}[/tex]must be a proper fraction)
[tex]\frac{4z}{8} = (4x +2)+ \frac{4}{8}[/tex]
Compare this to the formula [tex]\frac{Dividend}{Divisor}= Quotient + \frac{Remainder}{Divisor}[/tex]
The remainder is 4
Hence, the remainder when 4z is divided by 8 is 4.
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