The concentrations of sulfuric acid in the original containers as per the system of equation is equals to 24% in first container and 3% in second container.
What is system of equation?
" A system of equations is finite set of equations for which we find the common solution."
According to the question,
'a' represents the concentration of acid in first container
'b' represents the concentration of acid in second container
Situation1: 305 mL of the first solution and 580 mL of the second gives a mixture that is 10.24% acid, it represents the equation as,
a% of 305 + b% of 580 = 10.24% of 885
⇒ 305a + 580b = 9062.4 _______(1)
Situation 2:85 mL of the first mixed with 490mL of the second gives a 6.10% acid mixture, it represents the equation as,
a% of 85 + b% of 490 = 6.10% of 575
⇒ 85a + 490b = 3507.5 ______(2)
Solve system of equation by multiplying (1) by 85 and (2) by 305 we get,
25925a + 49300b = 770303 _______(3)
25925a + 149450b = 1069787.5 _______(4)
Subtract system of equation (3) from (4) we get,
100150b = 299483.5
⇒ b = 2.9
⇒ b≈ 3%
Substitute the value of 'b' in (2) we get,
85a + 490(3) = 3507.5
⇒85a + 1407 = 3507.5
⇒ 85a = 2037.5
⇒ a = 23.9
⇒ a ≈24%
Hence, concentration of sulfuric acid in first container 24% and second container 3% as per the system of equation.
Learn more about system of equation here
https://brainly.com/question/12895249
#SPJ3
