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In experiment 1, how many moles of benzoic acid are present? how many moles of sodium bicarbonate are contained in 1 ml of a 10% aqueous solution? (a 10% solution has 1 g of solute in 9 ml of solvent.) is the amount of sodium bicarbonate sufficient to react with all of the benzoic acid?

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First, let us calculate the moles of solute or sodium bicarbonate is in the 1 ml solution.

moles  = 1 mL * (1 g / 9 mL) = 0.11 moles

 

The molar mass of sodium bicarbonate is 84 g/mol, therefore the mass is:

mass = 0.11 moles * 84 g/mol

mass = 9.33 g

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