Respuesta :
Answer:
Triangle ABC is an isosceles triangle.
Step-by-step explanation:
Let AD represent both the median and altitude of triangle ABC.
A median divides the side in two equal parts so BD=BC.
An altitude is a perpendicular drawn .A perpendicular makes an angle of 90°. Hence <ADB=<ADC=90°
AD is the side common to both the triangles ADB and ADC.
Hence Δ ADB≅ΔADC by SAS congruence postulate.
So AB=AC by c.p .c .t.c(congruent parts of congruent triangles are congruent)
Hence by definition of Isosceles triangle ΔABC is an isosceles triangle.
