Respuesta :
a) First find the slope of the two coordinates given.
Slope = y2 - y1 / x2 - x1
Substitute the values of the coordinates. It doesn't matter which coordinate is x1 or x2 as long as thereby value corresponds.
Slope = -5 - 4 / 2 - (-10)
Slope = -9 / 12
Slope = -3/4
Then, plug in either of the coordinates into the equation of a line.
y - y1 = m(x - x1)
y - 4 = -3/4(x - (-10)
y - 4 = -3/4(x + 10)
y - 4 = -3/4x - 7.5
y = -3/4x - 3.5
Check if using the other coordinate makes a difference.
y - (-5) = -3/4(x - 2)
y + 5 = -3/4x + 1.5
y = -3/4x - 3.5
The equation of a line for these coordinates is:
y = -3/4x - 3.5
2) Just apply the same concept for the second one :)
Slope = y2 - y1 / x2 - x1
Substitute the values of the coordinates. It doesn't matter which coordinate is x1 or x2 as long as thereby value corresponds.
Slope = -5 - 4 / 2 - (-10)
Slope = -9 / 12
Slope = -3/4
Then, plug in either of the coordinates into the equation of a line.
y - y1 = m(x - x1)
y - 4 = -3/4(x - (-10)
y - 4 = -3/4(x + 10)
y - 4 = -3/4x - 7.5
y = -3/4x - 3.5
Check if using the other coordinate makes a difference.
y - (-5) = -3/4(x - 2)
y + 5 = -3/4x + 1.5
y = -3/4x - 3.5
The equation of a line for these coordinates is:
y = -3/4x - 3.5
2) Just apply the same concept for the second one :)
The required equation of the line passing through the coordinates (−10, 4), (2, −5) is 4y+3x = -14
The required equation of the line passing through the coordinates (5, 7), (−6, −3) is 11y-10x = -27
The formula for finding the equation of a line is expressed as:
[tex]y-y_0=m(x-x_0)\\[/tex]
Given the coordinates (−10, 4), (2, −5)
Get the slope:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]m=\frac{-5-4}{2-(-10)} \\m=\frac{-9}{12}\\m=\frac{-3}{4}[/tex]
Get the required equation
[tex]y-4=-3/4(x+10)\\4(y-4)=3(x+10)\\4y-16=-3x-30\\4y + 3x = -30+16\\4y+3x = -14\\[/tex]
b) For the equation of the line with the coordinates (5,7) and (-6, -3)
Get the slope
m = -3-7/-6-5
m = -10/-11
m = 10/11
The required equation will be:
y - 7 = 10/11(x-5)
11(y-7) = 10(x-5)\
11y - 77 = 10x - 50
11y - 10x = -50 + 77
11y - 10x = -27
Hence the required equation of the line passing through the coordinates (5, 7), (−6, −3) is 11y-10x = -27
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