Respuesta :
Facts:
Light year= [tex]9.5[/tex] × [tex] 10^{12} [/tex]
1 Mile= 1.609 kilometers
Milky way galaxy= 100,000 light years
e+x= Ten to the power of a number
A. What is the diameter of the Milky way in kilometers?
[tex]9.5 [/tex] × [tex] 10^{12} [/tex] × [tex]100,000[/tex] which is [tex]9.5e+17km [/tex]
Milky way Diameter in light years: [tex]9.5e+17km[/tex]
B. The speed of light is about [tex]3[/tex]×[tex]10^{8} [/tex] [tex]m/s[/tex]. What is the speed of light in kilometers? Hours?
B.1 [tex]3[/tex]×[tex] 10^{8} [/tex]×[tex]1.609[/tex] which is [tex]4.827e+8km[/tex]
Different calculations based on the estimated numbers you gave and the actual numbers came with different results. I did it based on what you gave which is [tex]4.827e+8km[/tex] rather than 4.828e
B.2 [tex]3[/tex]×[tex] 10^{8} [/tex]×[tex]60[/tex](//seconds in minute)×[tex]60[/tex](//minutes in a hour) which is [tex]1.08e+12[/tex][tex]m/h[/tex]
C. [tex]4.827e+12km[/tex]x must equal [tex]9.5e+17km[/tex]
So [tex]9.5e+17km[/tex]÷[tex]4.827e +8km[/tex] which is [tex]1,968,096,125.96[/tex] then you divide by 60 for minutes, another 60 for hours then 24 for each day which is [tex]22778.890307[/tex]≈[tex]22778.89[/tex]
D. You take what resulted in step C and divide by 365 which is [tex]22778.890307[/tex]÷365= [tex]62.4079187582[/tex]≈62.4079 years
So as you can see, if I round up numbers, it will vary but they should round 62 years or at least a number near it. This is the best that I can do. Hope I helped and remember to check for yourself that I did it right.
Light year= [tex]9.5[/tex] × [tex] 10^{12} [/tex]
1 Mile= 1.609 kilometers
Milky way galaxy= 100,000 light years
e+x= Ten to the power of a number
A. What is the diameter of the Milky way in kilometers?
[tex]9.5 [/tex] × [tex] 10^{12} [/tex] × [tex]100,000[/tex] which is [tex]9.5e+17km [/tex]
Milky way Diameter in light years: [tex]9.5e+17km[/tex]
B. The speed of light is about [tex]3[/tex]×[tex]10^{8} [/tex] [tex]m/s[/tex]. What is the speed of light in kilometers? Hours?
B.1 [tex]3[/tex]×[tex] 10^{8} [/tex]×[tex]1.609[/tex] which is [tex]4.827e+8km[/tex]
Different calculations based on the estimated numbers you gave and the actual numbers came with different results. I did it based on what you gave which is [tex]4.827e+8km[/tex] rather than 4.828e
B.2 [tex]3[/tex]×[tex] 10^{8} [/tex]×[tex]60[/tex](//seconds in minute)×[tex]60[/tex](//minutes in a hour) which is [tex]1.08e+12[/tex][tex]m/h[/tex]
C. [tex]4.827e+12km[/tex]x must equal [tex]9.5e+17km[/tex]
So [tex]9.5e+17km[/tex]÷[tex]4.827e +8km[/tex] which is [tex]1,968,096,125.96[/tex] then you divide by 60 for minutes, another 60 for hours then 24 for each day which is [tex]22778.890307[/tex]≈[tex]22778.89[/tex]
D. You take what resulted in step C and divide by 365 which is [tex]22778.890307[/tex]÷365= [tex]62.4079187582[/tex]≈62.4079 years
So as you can see, if I round up numbers, it will vary but they should round 62 years or at least a number near it. This is the best that I can do. Hope I helped and remember to check for yourself that I did it right.