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In an assembly operation at a furniture factory, six employees assembled an average of 450 standard dining chairs per 5-day week. what is the labor productivity of this operation?
a. 90 chairs/worker/day
b. 20 chairs/worker/day
c. 15 chairs/worker/day
d. 75 chairs/worker/day
e. none of the above

Respuesta :

SignoraPenguino
I believe the answer would be C.
 Because you are dividing the dining chairs by the number of workers... That would give you the total amount of chairs that each worker assembled. Then you divide that by the 5 days and you would get the number of chairs that each worker assembled each day.

So, the answer would be C

  

Answer:

c. 15 chairs/worker/day

Explanation:

Given the following information,

Number of employees = 6

Average number of chairs assembled = 450

Number of days = 5

The average number of chars assembled by per worker per day

= 450/(6 × 5)

= 450/30

= 15

It means that 1 worker would assemble an average of 15 chairs per day.

Option c. 15 chairs/worker/day is right.

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