Respuesta :
first off, let's convert the mixed fraction to "improper", and then divide then.
[tex]\bf \stackrel{mixed}{3\frac{2}{3}}\implies \cfrac{3\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{11}{3}}\\\\ -------------------------------\\\\ \cfrac{3\frac{2}{3}}{\frac{1}{3}}\implies \cfrac{\quad \frac{11}{3}\quad }{\frac{1}{3}}\implies \cfrac{11}{3}\cdot \cfrac{3}{1}\implies \cfrac{33}{3}\implies 11[/tex]
[tex]\bf \stackrel{mixed}{3\frac{2}{3}}\implies \cfrac{3\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{11}{3}}\\\\ -------------------------------\\\\ \cfrac{3\frac{2}{3}}{\frac{1}{3}}\implies \cfrac{\quad \frac{11}{3}\quad }{\frac{1}{3}}\implies \cfrac{11}{3}\cdot \cfrac{3}{1}\implies \cfrac{33}{3}\implies 11[/tex]
Let's start by changing -3 2/3 into an improper fraction of -11/3. Now let us set it up: -11/3 ÷ 1/3 which changes to multiplication to : -11/3 • 3/1= -33/3=-11. Soluton is -11.
