We are given that
A line passes through two points as
(0,-3) and (4,-1)
[tex](x_1,y_1)=(0,-3)[/tex]
[tex]x_1=0,y_1=-3[/tex]
[tex](x_2,y_2)=(4,-1)[/tex]
[tex]x_2=4,y_2=-1[/tex]
Firstly, we can find slope
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
now, we can plug values
[tex]m=\frac{-1+3}{4-0}[/tex]
[tex]m=\frac{2}{4}[/tex]
[tex]m=\frac{1}{2}[/tex]
now, we can use point slope form of line
[tex]y-y_1=m(x-x_1)[/tex]
we can plug values
[tex]y+3=\frac{1}{2} (x-0)[/tex]
[tex]y+3=\frac{1}{2}x[/tex]
[tex]y=\frac{1}{2}x-3[/tex]
so, the equation of line is
[tex]y=\frac{1}{2}x-3[/tex]...............Answer
