The compression forces acting on both sides of the center board = 70.338 N
Further explanation
The force acting on a system with static equilibrium is 0
[tex] \large {\boxed {\bold {\sum F = 0}} [/tex]
(forces acting as translational motion only, not including rotational forces)
[tex] \displaystyle \sum F_x = 0 \\\\\ sum F_y = 0 [/tex]
For objects undergoing rotation, the equilibrium must be met
[tex] \large {\boxed {\bold {\sum \tau = 0}} [/tex]
The force acting on the touchpad between the two fields is called the normal force (N)
While the frictional force arises because of 2 objects that come into direct contact, especially when there is motion between two objects that are in direct contact.
There are 2 friction forces
- static friction: fs = us.N
- kinetic friction: fk = uk .N
The board sandwiched between two other boards will not fall if
a downward force = an upward force
or ΣFy = 0 (idle / equilibrium)
so that
A downward force = weight of the board sandwiched = 87.5 N
An upward force = arises from two static friction forces namely: us.N (N = reaction force of the compression forces=F) ---> us.F
then the force that works can be stated:
EFy = 0
W = 2fs
W = 2 (us.F)
87.5 N = 2 (0.622. F)
F = 70,338 N
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