Hanna tosses a ball straight up with enough speed to remain in the air for several seconds?
a.what is the velocity of the ball when it reaches its highest point?
b.what is the velocity 1 s before it reaches its highest point?
c.what is the change in its velocity during this 1-s interval?
d.what is its velocity 1 s after it reaches its highest point?
e.what is the change in velocity during this 1-s interval?
f.what is the change in velocity during the 2-s interval(caution velocity not speed)?
g.what is the acceleration of the ball during any of these time intervals and at the moment the ball has zero velocity

In the free fall motion we have that the acceleration is constant and produced by gravity, this acceleration has a magnitude of 32 ft/s2 or 9.8 m/s2 depending on the units you are working with. This means that every second the speed changes a magnitude of 32 ft/2, the velocity will depend of whether the ball is going upward (positive) or downward (negative).

A) At the highest point the ball stops to start the descend, here v=0 ft/s

B) +32 ft/s. The vector is going up, in the next second the velocity is going to be 0 (negative acceleration)

C) V=vf-vo=0-32=-32 ft/s is the constant change in velocity in projectile motion

D) -32 ft/s. The vector is pointing downward

E) V=vf-vo=-32-0=-32 ft/s is the constant change in velocity in projectile motion, 32 ft/s per second

F) Delta V=vf-vo=-32-32=-72 ft/s

g) gravity acceleration is constant 32 ft/s2 (pointing downward vector)