Respuesta :
they tricked me into signing into this site to get the answer, oonly to find out they didnt have it answered, click b8
Using the normal distribution, it is found that the statement is False, thus the correct option is b.
In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
- It measures how many standard deviations the measure is from the mean.
- After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- The area on the tail beyond z is the proportion that is above z, that is, 1 subtracted by the p-value of z.
For this problem, z = 0.3 has a p-value of 0.6554.
1 - 0.6554 = 0.3446
The proportion in the tail beyond z = 0.30 is p = 0.3446, thus, the statement is False.
A similar problem is given at https://brainly.com/question/12518252
