Respuesta :
ΔE = 0
(m_alum) (c_alum) Δt - (m_water)(c_water) Δt' = 0
(30) (897) (20) - (20)(4186) Δt' = 0
Δt' = 6.42857 °C
(m_alum) (c_alum) Δt - (m_water)(c_water) Δt' = 0
(30) (897) (20) - (20)(4186) Δt' = 0
Δt' = 6.42857 °C