12z - 3 ≥ 2z - 15
When you have to solve an equality like that, you need to put the variables apart (the numbers with letters) and the numbers apart.
So first, we need to reunite the variables, by subtracting "2z" from both sides of the equation:
12z - 3 ≥ 2z -15
12z - 2z - 3 ≥ 2z - 2z - 15
12z - 2z - 3 ≥ -15
10z - 3 ≥ 15
Then we add 3 to both sides:
10z - 3 + 3 ≥ -15 + 3
10z ≥ -12
Now divide both sides by 10
(10z)/10 ≥ -12/10
z ≥ -6/5
Now we need to write the answer as a mixed number.
-6/5 = -1.2
0.2 = 1/5
9
So -6/5 = -1 1/5.
So 12z - 3 ≥ 2z - 15 for Z ≥ -1 1/5
Hope this helps! :)
