Respuesta :
If we leftover 1 toothbrush, we will have:
56 tubes of toothpaste, 112 packets of floss and 84 toothbrushes.
The greatest common factor:
GCF ( 56, 112, 84 ) = 28
56 : 28 = 2, 112 : 28 = 4, 84 : 28 = 3
Answer:
The greatest number of identical dental care bags is 28.
In every bag will be 2 tubes of toothpaste, 4 packets of floss and 3 toothbrushes. One toothbrush will be leftover.
56 tubes of toothpaste, 112 packets of floss and 84 toothbrushes.
The greatest common factor:
GCF ( 56, 112, 84 ) = 28
56 : 28 = 2, 112 : 28 = 4, 84 : 28 = 3
Answer:
The greatest number of identical dental care bags is 28.
In every bag will be 2 tubes of toothpaste, 4 packets of floss and 3 toothbrushes. One toothbrush will be leftover.
Greatest number of identical dental care bags is equal to the L.C.M. of 56, 112 & 85.
56 = 2 x 2 x 2 x 7
112 = 2 x 2 x 2 x 2 x 7
85 = 5 x 17
L.C.M. (56, 112, 85) = 2 x 2 x 2 x 2 x 5 x 7 x 17
= 560 x 17
= 9520
Therefore, 9520 is the correct answer.
56 = 2 x 2 x 2 x 7
112 = 2 x 2 x 2 x 2 x 7
85 = 5 x 17
L.C.M. (56, 112, 85) = 2 x 2 x 2 x 2 x 5 x 7 x 17
= 560 x 17
= 9520
Therefore, 9520 is the correct answer.