From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 1980?

An increase of 25% is represented by the multiplier 1.00 + 0.25, or 1.25.
Then Lior's 1980 weight, mult. by 1.25, results in his 1990 weight, or k kg.

Let his 1980 weight be w. Then 1.25w = k. Divide both sides by 1.25 to obtain w, Lior's 1980 weight:

1.25 w = k
--------- ------- = (4/5)k, or 4k/5 (answer)
1.25 1.25

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abidemiokin abidemiokin · Answer 2 · 2021-10-05T13:00:54+02:00

Ththe weight of Lior in 1990 in terms of k is [tex]\frac{4}{5} k[/tex]

Let the weight of Lior in 1980 be "w"

If Lior's weight increased by 25%, his new weight was "k". This can be expressed as:

w + (25% of w) = k

w + (0.255w) = k

w + 0.15w = k

1.25w = k

Divide both sides by 1.25

[tex]\frac{1.25w}{1.25} =\frac{k}{1.25} \\w=\frac{k}{1.25} \\w=\frac{100k}{125} \\w=\frac{4}{5}k[/tex]

This shows that the weight of Lior in 1990 in terms of k is [tex]\frac{4}{5} k[/tex]

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