The answer:
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x = (⅔)y ;
y = 3x/2.
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Given:
x + (⅓)y + x - (2/4)y - x = (3/6)y ;
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Take the: x + x - x = 1x + 1x - 1x = 2x - 1x = 1x = x ;
and rewrite:
x + (⅓)y - (2/4)y = (3/6)y ;
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Note that: (2/4)y = (½)y ;
and: (3/6)y = (½)y ; so;
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Rewrite as:
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x + (⅓)y - (½)y = (½)y ;
Add "(½)y" to EACH SIDE of the equation;
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x + (⅓)y - (½)y + (½)y = (½)y + (½)y ;
to get: x + (⅓)y = y ;
x = 1y - (⅓)y = (3/3) y - (1/3)y - [ (3-1)/3] y = (⅔)y ;
So: x = (⅔)y ;
In terms of "y" ;
Given: (⅔)y = x ; Multiply each side of the equation by "3" ;
3*[(⅔)y] = 3*x ;
to get: 2y = 3x ;
Now, divide EACH SIDE of the equation by "2" ; to isolate "y" on one side of the equation; and to solve for "y" (in terms of "x"):
2y / 2 = 3x / 2 ;
to get:
y = 3x/2 ;
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