Respuesta :
The area of a triangle is A=1/2*b*h
When we graph the vertices of the triangle on a graph, we see that the lowest points are at y=-2, and the highest point is at y=1. Therefore, our height is 3.
The base of the triangle goes from (0,-2) to (8,-2), which gives us a length of 8 for our base.
A=1/2*(8)*(3)
A=12
When we graph the vertices of the triangle on a graph, we see that the lowest points are at y=-2, and the highest point is at y=1. Therefore, our height is 3.
The base of the triangle goes from (0,-2) to (8,-2), which gives us a length of 8 for our base.
A=1/2*(8)*(3)
A=12
Answer:
12 square unit.
Step-by-step explanation:
Since, the area of a triangle having vertices [tex](x_1, y_1)[/tex], [tex](x_2, y_2)[/tex] and [tex](x_3, y_3)[/tex] is,
[tex]A=\frac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|[/tex]
Here, the vertices of the triangle are (0, −2), (8, −2) and (9, 1),
Hence, area of the given triangle is,
[tex]A=\frac{1}{2}|0(-2-1)+8(1+2)+9(-2+2)|[/tex]
[tex]=\frac{1}{2}| 0+24+0|[/tex]
[tex]=\frac{24}{2}[/tex]
[tex]=12\text{ square unit}[/tex]
