Respuesta :

[tex]\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) M&({{ 0}}\quad ,&{{ 6}})\quad % (c,d) N&({{ 5}}\quad ,&{{ 3}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ MN=\sqrt{(5-0)^2+(3-6)^2}\implies MN=\sqrt{5^2+(-3)^2} \\\\\\ MN=\sqrt{25+9}\implies \boxed{MN=\sqrt{34}}\\\\ [/tex]

[tex]\bf -------------------------------\\\\ \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) R&({{-7}}\quad ,&{{ -5}})\quad % (c,d) S&({{ -2}}\quad ,&{{ -2}}) \end{array}\quad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ RS=\sqrt{[-2-(-7)]^2+[-2-(-5)]^2} \\\\\\ RS=\sqrt{(-2+7)^2+(-2+5)^2}\implies RS=\sqrt{5^2+3^2} \\\\\\ RS=\sqrt{25+9}\implies \boxed{RS=\sqrt{34}}[/tex]

well, are they?