Answer: The area of the parallelogram with the given vertices=238 square units.
Step-by-step explanation:
Let CD be the base of the parallelogram ABCD is given by distance formula
CD=[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} =\sqrt{(-12-2)^2+(-5-(-5))^2} =\sqrt{196} =14[/tex]units[or you can count distance by using graph as ordinates of C and D are same to we can count the distance of x from C to D]
Now consider P a point on CD such that AP become the height of the parallelogram which is given by (from the graph attached)=17 [as abscissa of P and A are same to we can count the distance of y from A to P]
Area of parallelogram = base × height=14×17=238 square units.
