A stream of air (21 mole% o2, the rest n2) flowing at a rate of 10.0 kg/h is mixed with a stream of co2. the co2 enters the mixer at a rate of 20:0 m3/h at 150°c and 1.5 bar. what is the mole percent of co2 in the product stream?

Question

bubl3771 bubl3771

10-10-2017
Chemistry

contestada

A stream of air (21 mole% o2, the rest n2) flowing at a rate of 10.0 kg/h is mixed with a stream of co2. the co2 enters the mixer at a rate of 20:0 m3/h at 150°c and 1.5 bar. what is the mole percent of co2 in the product stream?

Respuesta :

Otras preguntas

Which company that sells inexpensive beer in the united states also sells an upscale beer in china for $44 a bottle?.

Which of these is correct ??

Voting Vocabulary Match the voting terms on the left with their definitions on the right. 1. Suppression 2. Disenfranchisement 3. Constituents 4. Gerrymandering

To promote respect for others and strengthen family relationship, create an advocacy poster that upholds the value of respect for others and that helps strength

Using point-slope form, write the equation of the line that passes through the point (−1,4) and has a slope of −3. step by step explanation will give 100 points

A cylinder has a circular base with a radius of 3units and a height of 7 units. What is the volume of the cylinder in cubic units?

Select the correct answer from each drop-down menu. The legs of a human and the limbs of a cat are similar in structure. These structures are called _______ st

Calculate the range, population variance, and population standard deviation for the following data set. If necessary, round to one more decimal place than the l

Question 9 of 10 If b is a positive real number and m and n are positive integers, then 5²³ª = √6² = (3√6)* · A. True B. False

The literature of the Harlem Renaissance

meerkat18 meerkat18 · Answer 1 · 2017-10-23T14:03:40+02:00

Molecular weight of air = 29 g/mole, moles of air entering = 5/29 kgmoles/hr= 0.1724 kg moles/hr
Moles of N2= 0.21*0.1724=0.036 kg moles/hr, moles of N2= 0.79*0.1724= 0.1362 kgmoles/hr
Moles of CO2 can be calculated from gas law equation, n= PV/RT
V= 25 m3/hr= 25* 1000 L/hr, P= 2 bar = 2*0.9869 atm,=1.9738 atm R= 0.0821 L.atm/mole.K T= 100 deg.c =100+?273.15= 373.15K
n= number of moles of CO2= 1.9738*25*1000/ (0.0821*373.15) =1611 moles/hr= 1.611 kg moles/hr
total moles of mixture = 0.1724 +1.611 =1.7834 kg moles/hr
Moles % CO2 in the mixed stram = 100*1.611/1.7834 = 90.33%
Answer is 90.33%