Answer:
(C)
Step-by-step explanation:
It is given that a right triangle, ACB which is right angled at C has BC = 24 inches, and AB = 25 inches.
We know that m∠C=90°,
Using the trigonometry in ΔACB, we have
[tex]sinB=\frac{AC}{AB}[/tex]
Substituting the given values, we get
⇒[tex]sinB=\frac{24}{25}[/tex]
⇒[tex]B=sin^{-1}(0.96)[/tex]
⇒[tex]B=73.7^{\circ}[/tex]
Also, [tex]sinA=\frac{CB}{AB}[/tex]
Substituting the given values, we get
⇒[tex]sinA=\frac{7}{25}[/tex]
⇒[tex]A=sin^{-1}(0.28)[/tex]
⇒[tex]A=16.3^{\circ}[/tex]
Therefore, the measure of the angles in triangle ABC are m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°.
Thus, option C is correct.
