Answer:
She can make maximum 2 pieces
Amount left = [tex] \frac{1}{12} [/tex] m
Explanation:
1- getting the maximum number of pieces:
We know that the total length is [tex] \frac{3}{4} [/tex] m and that each piece would measure [tex] \frac{1}{3} [/tex]
To get the number of pieces, we would simply divide the total length by the length of each piece as follows:
number of pieces = [tex] \frac{3}{4} / \frac{1}{3} = \frac{3}{4} * \frac{3}{1} = \frac{9}{4} = 2.25 [/tex] pieces
We will need to round down to get the maximum number of pieces.
This means that the maximum number of pieces that she can cut is 2 pieces
2- getting the leftover:
We calculated that she can make two pieces each of length [tex] \frac{1}{3} [/tex] m
This means that:
total length of two pieces = [tex] 2 * \frac{1}{3} = \frac{2}{3} [/tex] m
We know that the total length is [tex] \frac{3}{4} [/tex] m
This means that:
leftover = [tex] \frac{3}{4} - \frac{2}{3} = \frac{1}{12} [/tex] m
Hope this helps :)
The correct answer is:
2 pieces, with 1/12 m left over.
Explanation:
To find the number of 1/3 meter pieces she can cut from a 3/4 meter ribbon, we divide:
3/4÷1/3
To divide fractions, flip the second one and multiply:
3/4×3/1
To multiply fractions, multiply straight across:
(3*3)/(4*1) = 9/4
4 will go into 9 two times with 1 left over, so this simplifies to 2 1/4; this means she can cut 2 pieces this length.
2 pieces that are 1/3 meter long is a total of 2(1/3) = 2/3 m. To find out how much is left, subtract:
3/4 - 2/3
Common denominator is 12:
3/4 = 9/12 and 2/3 = 8/12
9/12 - 8/12 = 1/12
There is 1/12 of a meter left.
