As you can see in the reaction, for each [tex]3O_2[/tex] that reacts, two [tex]Fe_2O_3[/tex] are created.
There are [tex]\frac{96.0}{16}=6mol[/tex] of oxygens reacting, hence [tex]2*6/3=4[/tex] mols of iron will be oxidized, which represents [tex]24*55.8=\boxed{223g}[/tex]
