Respuesta :

AL2006

The distance between any two points is

       square root of ( [difference in the 'y's]² + [difference in the 'x's]² )

Difference in the 'y's =  8 - 2  =  6
Difference in the 'x's =  7 - (-1)  =  8

Distance between them =

           square root of  ( 6² + 8² )  =

           square root of  ( 36 + 64 )  =

           square root of  ( 100 )  =  10 .

Answer: 10

Step-by-step explanation: In this problem, we're asked to find the distance between the points (-1,2) and (7,8) so we use the distance formula which states that the distance between two points is equal to

[tex]d =\sqrt{(x^{2} - x^{1})^{2} + (y^{2} - y^{1})^{2} }[/tex].

Our first point, (-1,2) represents ([tex]^{x} 1[/tex], [tex]^{y}1[/tex]) and our second point,

(7,8) represents ([tex]^{x}2[/tex], [tex]^{y}2[/tex]).

So, plugging the given information into the formula, we have[tex]\sqrt{7 - (-1))^{2} + (8 - 2)^{2}}[/tex].

Next, we simplify inside the parentheses to get[tex]\sqrt{(8)^{2} + (6)^{2}}[/tex].

Next, 8² is 64 and 6² is 36 so we have [tex]\sqrt{64 + 36}[/tex] or [tex]\sqrt{100}[/tex] which is 10.

So the distance between the points (-1,2) and (7,8) is 10.