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NoBrainerS
240 = 2 × 120
120 = 2 × 60
60 = 2 × 30
30 = 2 × 15
15 = 3 × 5
The 2, 2, 2, 2, 3 and 5 are all the prime factors of 240. So, 2^4 × 3 × 5

1500 = 3 × 500
500 = 5 × 100
100 = 5 × 20
20= 5 × 4
4 = 2 × 2
The 3, 5, 5, 5, 2 and 2 are all the prime factors of 1500. So, 2² + 3 + 5³

Answer:

[tex]240=2^4\times 3\times 5[/tex]

[tex]1500=2^2\times 3\times 5^3[/tex]

Step-by-step explanation:

To find : Write 240 and 1500 as products of their prime factor ?

Solution :

We factor the number by dividing the least prime numbers,

2 | 240

2 | 120

2 | 60

2 | 30

3 | 15

5 | 5

  | 1

So, [tex]240=2\times 2\times 2\times 2\times 3\times 5[/tex]

or [tex]240=2^4\times 3\times 5[/tex]

2 | 1500

2 | 750

3 | 375

5 | 125

5 | 25

5 | 5

  | 1

So, [tex]1500=2\times 2\times 3\times 5\times 5\times 5[/tex]

or [tex]1500=2^2\times 3\times 5^3[/tex]

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