Respuesta :
Two things are given to us: The "molar mass" of NaOH and the number of molecules of NaOH.
The molar mass is different from "mass"; 1 mole of NaOH is equal to 40.0g/mol.
When the question asks, what is the mass? It is referring to how many grams there are.
First, we are going to convert the molecules to atoms using Avogadro's number (=6.02 x 10^23)
(2.50 x 10^22 molecules) x (6.02 x 10^23 atoms) = 0.042 mol
Next, we are going to convert from moles to grams.
0.042 mol of NaOH x 40.0 g of NaOH/1 mole = 1.68g of NaOH.
There are 1.68 grams in 2.50 x 10^22 molecules of NaOH.
The molar mass is different from "mass"; 1 mole of NaOH is equal to 40.0g/mol.
When the question asks, what is the mass? It is referring to how many grams there are.
First, we are going to convert the molecules to atoms using Avogadro's number (=6.02 x 10^23)
(2.50 x 10^22 molecules) x (6.02 x 10^23 atoms) = 0.042 mol
Next, we are going to convert from moles to grams.
0.042 mol of NaOH x 40.0 g of NaOH/1 mole = 1.68g of NaOH.
There are 1.68 grams in 2.50 x 10^22 molecules of NaOH.
Hello!
What is the mass of 2.50 ×1022 molecules of NaOH (Molar mass = 40.0 g/mol)?
Data:
Molar Mass of NaOH = 40 g/mol
Solving: According to the Law Avogradro, we have in 1 mole of a substance, 6.02x10²³ atoms/mol or molecules
1 mol -------------------- 6.02*10²³ molecules
y mol -------------------- 2.50*10²² molecules
[tex]\dfrac{1}{y} = \dfrac{6.02*10^{23}}{0.250*10^{23}}[/tex]
Product of extremes equals product of means
[tex]6.02*10^{23}*y = 0.250*10^{23}*1[/tex]
[tex]6.02*10^{23}\:y = 0.250*10^{23}[/tex]
[tex]y = \dfrac{0.250*10^{23}}{6.02*10^{23}}[/tex]
[tex]\boxed{y \approx 0.042\:mol}[/tex]
Solving: Find the mass value now
40 g ----------------- 1 mol of NaOH
x g ------------- 0.042 mol of NaOH
[tex]x = 40*0.042[/tex]
[tex]\boxed{\boxed{x = 1.68\:g}}\end{array}}\qquad\quad\checkmark[/tex]
Answer:
The mass is 1.68 grams
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I Hope this helps, greetings ... Dexteright02! =)