00 mL? I believe that you have erroneously pasted the question here.
Anyway, let us continue computing for the molarity of KOH but i will just use a variable “A” for the volume of H2SO4 solution.
The complete balanced reaction is:
H2SO4 + 2KOH --> K2SO4 + 2H2O
We see that 2 moles of KOH is needed for every mole of H2SO4. So calculate the moles of H2SO4.
moles H2SO4 = 0.245 M * (A / 1000) = 2.45x10^-4 A
So the number of moles of KOH is:
moles KOH = 2.45x10^-4 A * 2
moles KOH = 4.90x10^-4 A
So the molarity of KOH is:
Molarity KOH = 4.90x10^-4 A / (0.0239 L)
Molarity KOH = 0.0205 * A
Simply multiply 0.0205 by the correct volume of H2SO4 in ml
