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A circle is centered at the point (5, -4) and passes through the point (-3, 2).

The equation of this circle is (x +__ )^2 + (y +__ )^2 = __

Respuesta :

The equation of a circle with center (a, b) and center r, is:

                         [tex]\displaystyle{ (x-a)^2+(y-b)^2=r^2[/tex].


We have the center, so we can substitute a=5, and b=-4 in the equation. But we still need the radius.


The radius of a circle is the distance between the center (   (5, -4)  ) and any point of the circle (      (-3, 2)     ). Using the formula of the distance between 2 points, we have:

[tex]\displaystyle{ r= \sqrt{(5-(-3))^2+(-4-2)^2}= \sqrt{8^2+(-6)^2}= \sqrt{64+36}=10[/tex].

Substituting in the equation, we have:

[tex]\displaystyle{ (x-5)^2+(y-(-4))^2=10^2[/tex], 

that is [tex]\displaystyle{ (x-5)^2+(y+4)^2=100[/tex].


Answer: (x +_(-5)_ )^2 + (y +_4_ )^2 = _100_

Answer: The full equation would be (x + -5)^2 + (y + 4)^2 = 100

Step-by-step explanation: That is the correct answer on Plato/Edmentum.