Respuesta :

Answer:

K donates, or transfers, one electron to bromine, which has 7 electrons. Both K and Br are now stable with 8 electrons. K becomes a positive ion and Br becomes a negative ion. The positive K ion and the negative Br ion attract each other to form an ionic bond.

Explanation:

Sample Response on Edge

okpalawalter8

The K( potassium a metal) will give away one of its outer shell electron K+ to form a bond owning to the fact it belongs to the group A element and The Bromine(bromine a nonmetal) ion Br-  will form a bond with the K( potassium a metal)  having received its K+ ion.This will lead to the forming of KBr.

From the question we are told that

The process of ionic bond formation between K( potassium a metal) and Br(bromine a nonmetal)

Generally

Ionic bond formation

This is a method of bond formation where elements share electrons of the outer most shell to form a bond i.e electrons are been transferred from one atom to another

Therefore

It is important to note that the K( potassium a metal) will give away one of its outer shell electron K+ to form a bond owning to the fact it belongs to the group A element and The Bromine(bromine a nonmetal) ion Br-  will form a bond with the K( potassium a metal)  having received its K+ ion.This will lead to the forming of KBr.

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