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What is the equation of the line shown in the graph? A function graph of a line with two points (-3,-2) and (-1,2) with an x axis of negative five to five and a y axis of negative five to five Drag and drop the expressions to write the equation of the line in slope-intercept form. y = ＿ + ＿　阿ㄐ高

Respuesta :

Aethis
y=(1/2 x)-2

My Work:
Say that the slop is "a" and that the y-intercept is "b".

For the slope:
First coordinate equation: -3=-2a+b
Second coordinate equation: -1=2a+b
Combine the equations. -3-(-1)=-2a-(2a)+b-(b)
Break down the parenthesis. -3+1=-2a-2a+b-b
Simplify the equation. -2=-4a
Divide both sides by -4 to get the answer to the slope. a=1/2

For the y-intercept:
Use the second coordinate's equation and the now known slope. -3=-2*1/2+b
Multiply -2 by 1/2 (Order of Operations). -3=-1+b
Add +1 to both sides to cancel the -1. -3+1=b
Finally, solve the solve -3+1 to get the answer to the y-intercept. b=-2
profantoniofonte

Answer:

[tex]y=2x+4[/tex]

Step-by-step explanation:

1) Finding out the slope:

[tex](-3,-2) ; (-1,2)[/tex]

[tex]m=\frac{y-y_{0}}{x-x_{0}}=\frac{2+2}{-1+3}\Rightarrow m=\frac{4}{2}\Rightarrow m= 2[/tex]

2) Finding the linear parameter. Just plug in one of the points (2,-2).

[tex]y=2x+b\Rightarrow -2=2(-3)+b\Rightarrow 6-2=b\Rightarrow b=4\\y=2x+4[/tex]

3) The slope intercept form, is when we place the y on the left side, and the mx and b parameters on the right side:

[tex]y=mx +b \Rightarrow y=2x+4[/tex]

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