suppose P = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} and V = {2, 4, 6, 8, 10, 12, 14, 16, 18, 20}. what is P ∩ V
a. {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 14, 16, 18, 20}
b. {0, 1, 3, 5, 7, 9}
c. {10, 12, 14, 16, 18, 20}
d. {2, 4, 6, 8}** 

the answer is D.

Respuesta :

The answer is D, because those are the numbers that are found in both sets

The correct option is D because [tex]P\cap V=\{2,4,6,8\}[/tex].

Given:

The given sets are:

[tex]P=\{0, 1, 2, 3, 4, 5, 6, 7, 8, 9\}[/tex]

[tex]V=\{2, 4, 6, 8, 10, 12, 14, 16, 18, 20\}[/tex]

To find:

The set [tex]P\cap V[/tex].

Explanation:

The intersection of two sets is the set that contains common elements.

Common elements of set P and set V are [tex]2,4,6,8[/tex].

[tex]P\cap V=\{2,4,6,8\}[/tex]

Therefore, the correct option is D.

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