Answer:
Not factorable.
Step-by-step explanation:
Since the middle term is 64/3 which cannot be simplified into a whole number, the quadratic can not be factored. To factor when a is not 1, multiply 5 and 17 to get 85. Then find two numbers which multiply to 85 and add to -64/3 or -21.333.... It cannot be done. Instead solve using the quadratic formula.
The quadratic formula is [tex]x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}[/tex]. Here a=5, b=-64/3, and c=17.
Substitute and you'll have:
[tex]x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{\frac{64}{3}+/-\sqrt{{\frac{64}{3}}^2-4(5)(17)} }{2(5)}=\frac{21.333..+/-\sqrt{455.1111...-340} }{10)}[/tex]
[tex]\frac{21.333..+/-\sqrt{115.1111...} }{10)} = \frac{21.333..+/- 10.73}{10)} = 3.2, 1.06[/tex]
These are approximations since 64/3 and other numbers were rounded in the calculation.